Integrand size = 26, antiderivative size = 45 \[ \int \frac {\cos (c+d x)}{a \cos (c+d x)+b \sin (c+d x)} \, dx=\frac {a x}{a^2+b^2}+\frac {b \log (a \cos (c+d x)+b \sin (c+d x))}{\left (a^2+b^2\right ) d} \]
[Out]
Time = 0.07 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {3177, 3212} \[ \int \frac {\cos (c+d x)}{a \cos (c+d x)+b \sin (c+d x)} \, dx=\frac {b \log (a \cos (c+d x)+b \sin (c+d x))}{d \left (a^2+b^2\right )}+\frac {a x}{a^2+b^2} \]
[In]
[Out]
Rule 3177
Rule 3212
Rubi steps \begin{align*} \text {integral}& = \frac {a x}{a^2+b^2}+\frac {b \int \frac {b \cos (c+d x)-a \sin (c+d x)}{a \cos (c+d x)+b \sin (c+d x)} \, dx}{a^2+b^2} \\ & = \frac {a x}{a^2+b^2}+\frac {b \log (a \cos (c+d x)+b \sin (c+d x))}{\left (a^2+b^2\right ) d} \\ \end{align*}
Time = 0.23 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.91 \[ \int \frac {\cos (c+d x)}{a \cos (c+d x)+b \sin (c+d x)} \, dx=\frac {a (c+d x)+b \log (a \cos (c+d x)+b \sin (c+d x))}{\left (a^2+b^2\right ) d} \]
[In]
[Out]
Time = 0.46 (sec) , antiderivative size = 62, normalized size of antiderivative = 1.38
method | result | size |
derivativedivides | \(\frac {\frac {-\frac {b \ln \left (1+\tan \left (d x +c \right )^{2}\right )}{2}+a \arctan \left (\tan \left (d x +c \right )\right )}{a^{2}+b^{2}}+\frac {b \ln \left (a +b \tan \left (d x +c \right )\right )}{a^{2}+b^{2}}}{d}\) | \(62\) |
default | \(\frac {\frac {-\frac {b \ln \left (1+\tan \left (d x +c \right )^{2}\right )}{2}+a \arctan \left (\tan \left (d x +c \right )\right )}{a^{2}+b^{2}}+\frac {b \ln \left (a +b \tan \left (d x +c \right )\right )}{a^{2}+b^{2}}}{d}\) | \(62\) |
parallelrisch | \(\frac {a x d -b \ln \left (\sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )+b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-a \right )}{d \left (a^{2}+b^{2}\right )}\) | \(66\) |
risch | \(-\frac {x}{i b -a}-\frac {2 i b x}{a^{2}+b^{2}}-\frac {2 i b c}{d \left (a^{2}+b^{2}\right )}+\frac {b \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-\frac {i b +a}{i b -a}\right )}{d \left (a^{2}+b^{2}\right )}\) | \(89\) |
norman | \(\frac {\frac {a x}{a^{2}+b^{2}}+\frac {a x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{a^{2}+b^{2}}}{1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}+\frac {b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-a \right )}{d \left (a^{2}+b^{2}\right )}-\frac {b \ln \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )}{d \left (a^{2}+b^{2}\right )}\) | \(127\) |
[In]
[Out]
none
Time = 0.26 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.36 \[ \int \frac {\cos (c+d x)}{a \cos (c+d x)+b \sin (c+d x)} \, dx=\frac {2 \, a d x + b \log \left (2 \, a b \cos \left (d x + c\right ) \sin \left (d x + c\right ) + {\left (a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} + b^{2}\right )}{2 \, {\left (a^{2} + b^{2}\right )} d} \]
[In]
[Out]
Result contains complex when optimal does not.
Time = 1.07 (sec) , antiderivative size = 296, normalized size of antiderivative = 6.58 \[ \int \frac {\cos (c+d x)}{a \cos (c+d x)+b \sin (c+d x)} \, dx=\begin {cases} \frac {\tilde {\infty } x \cos {\left (c \right )}}{\sin {\left (c \right )}} & \text {for}\: a = 0 \wedge b = 0 \wedge d = 0 \\\frac {\log {\left (\sin {\left (c + d x \right )} \right )}}{b d} & \text {for}\: a = 0 \\- \frac {d x \sin {\left (c + d x \right )}}{2 i b d \sin {\left (c + d x \right )} + 2 b d \cos {\left (c + d x \right )}} + \frac {i d x \cos {\left (c + d x \right )}}{2 i b d \sin {\left (c + d x \right )} + 2 b d \cos {\left (c + d x \right )}} - \frac {\cos {\left (c + d x \right )}}{2 i b d \sin {\left (c + d x \right )} + 2 b d \cos {\left (c + d x \right )}} & \text {for}\: a = - i b \\- \frac {d x \sin {\left (c + d x \right )}}{- 2 i b d \sin {\left (c + d x \right )} + 2 b d \cos {\left (c + d x \right )}} - \frac {i d x \cos {\left (c + d x \right )}}{- 2 i b d \sin {\left (c + d x \right )} + 2 b d \cos {\left (c + d x \right )}} - \frac {\cos {\left (c + d x \right )}}{- 2 i b d \sin {\left (c + d x \right )} + 2 b d \cos {\left (c + d x \right )}} & \text {for}\: a = i b \\\frac {x \cos {\left (c \right )}}{a \cos {\left (c \right )} + b \sin {\left (c \right )}} & \text {for}\: d = 0 \\\frac {a d x}{a^{2} d + b^{2} d} + \frac {b \log {\left (\cos {\left (c + d x \right )} + \frac {b \sin {\left (c + d x \right )}}{a} \right )}}{a^{2} d + b^{2} d} & \text {otherwise} \end {cases} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 124 vs. \(2 (45) = 90\).
Time = 0.30 (sec) , antiderivative size = 124, normalized size of antiderivative = 2.76 \[ \int \frac {\cos (c+d x)}{a \cos (c+d x)+b \sin (c+d x)} \, dx=\frac {\frac {2 \, a \arctan \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{2} + b^{2}} + \frac {b \log \left (-a - \frac {2 \, b \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {a \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}\right )}{a^{2} + b^{2}} - \frac {b \log \left (\frac {\sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + 1\right )}{a^{2} + b^{2}}}{d} \]
[In]
[Out]
none
Time = 0.30 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.64 \[ \int \frac {\cos (c+d x)}{a \cos (c+d x)+b \sin (c+d x)} \, dx=\frac {\frac {2 \, b^{2} \log \left ({\left | b \tan \left (d x + c\right ) + a \right |}\right )}{a^{2} b + b^{3}} + \frac {2 \, {\left (d x + c\right )} a}{a^{2} + b^{2}} - \frac {b \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{2} + b^{2}}}{2 \, d} \]
[In]
[Out]
Time = 23.01 (sec) , antiderivative size = 1069, normalized size of antiderivative = 23.76 \[ \int \frac {\cos (c+d x)}{a \cos (c+d x)+b \sin (c+d x)} \, dx=\frac {b\,\ln \left (-a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+2\,b\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )+a\right )}{d\,\left (a^2+b^2\right )}-\frac {2\,a\,\mathrm {atan}\left (\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (\frac {\left (a^4-13\,a^2\,b^2+4\,b^4\right )\,\left (\frac {a^3\,\left (96\,a^3\,b^2+96\,a\,b^4\right )}{{\left (a^2+b^2\right )}^3}+\frac {a\,\left (96\,a\,b^2-32\,a^3+\frac {b\,\left (32\,a\,b^3+128\,a^3\,b-\frac {b\,\left (96\,a^3\,b^2+96\,a\,b^4\right )}{a^2+b^2}\right )}{a^2+b^2}\right )}{a^2+b^2}+\frac {b\,\left (\frac {a\,\left (32\,a\,b^3+128\,a^3\,b-\frac {b\,\left (96\,a^3\,b^2+96\,a\,b^4\right )}{a^2+b^2}\right )}{a^2+b^2}-\frac {a\,b\,\left (96\,a^3\,b^2+96\,a\,b^4\right )}{{\left (a^2+b^2\right )}^2}\right )}{a^2+b^2}\right )}{{\left (a^4+5\,a^2\,b^2+4\,b^4\right )}^2}-\frac {6\,a\,b\,\left (a^2-2\,b^2\right )\,\left (32\,a\,b-\frac {b\,\left (96\,a\,b^2-32\,a^3+\frac {b\,\left (32\,a\,b^3+128\,a^3\,b-\frac {b\,\left (96\,a^3\,b^2+96\,a\,b^4\right )}{a^2+b^2}\right )}{a^2+b^2}\right )}{a^2+b^2}+\frac {a\,\left (\frac {a\,\left (32\,a\,b^3+128\,a^3\,b-\frac {b\,\left (96\,a^3\,b^2+96\,a\,b^4\right )}{a^2+b^2}\right )}{a^2+b^2}-\frac {a\,b\,\left (96\,a^3\,b^2+96\,a\,b^4\right )}{{\left (a^2+b^2\right )}^2}\right )}{a^2+b^2}-\frac {a^2\,b\,\left (96\,a^3\,b^2+96\,a\,b^4\right )}{{\left (a^2+b^2\right )}^3}\right )}{{\left (a^4+5\,a^2\,b^2+4\,b^4\right )}^2}\right )\,\left (a^4+2\,a^2\,b^2+b^4\right )}{32\,a^2}+\frac {\left (a^4-13\,a^2\,b^2+4\,b^4\right )\,\left (\frac {a\,\left (32\,a^2\,b-\frac {b\,\left (64\,a^2\,b^2-32\,a^4+\frac {b\,\left (96\,a^4\,b+96\,a^2\,b^3\right )}{a^2+b^2}\right )}{a^2+b^2}\right )}{a^2+b^2}+\frac {a^3\,\left (96\,a^4\,b+96\,a^2\,b^3\right )}{{\left (a^2+b^2\right )}^3}-\frac {b\,\left (\frac {a\,\left (64\,a^2\,b^2-32\,a^4+\frac {b\,\left (96\,a^4\,b+96\,a^2\,b^3\right )}{a^2+b^2}\right )}{a^2+b^2}+\frac {a\,b\,\left (96\,a^4\,b+96\,a^2\,b^3\right )}{{\left (a^2+b^2\right )}^2}\right )}{a^2+b^2}\right )\,\left (a^4+2\,a^2\,b^2+b^4\right )}{32\,a^2\,{\left (a^4+5\,a^2\,b^2+4\,b^4\right )}^2}+\frac {3\,b\,\left (a^2-2\,b^2\right )\,\left (\frac {b\,\left (32\,a^2\,b-\frac {b\,\left (64\,a^2\,b^2-32\,a^4+\frac {b\,\left (96\,a^4\,b+96\,a^2\,b^3\right )}{a^2+b^2}\right )}{a^2+b^2}\right )}{a^2+b^2}+\frac {a\,\left (\frac {a\,\left (64\,a^2\,b^2-32\,a^4+\frac {b\,\left (96\,a^4\,b+96\,a^2\,b^3\right )}{a^2+b^2}\right )}{a^2+b^2}+\frac {a\,b\,\left (96\,a^4\,b+96\,a^2\,b^3\right )}{{\left (a^2+b^2\right )}^2}\right )}{a^2+b^2}+\frac {a^2\,b\,\left (96\,a^4\,b+96\,a^2\,b^3\right )}{{\left (a^2+b^2\right )}^3}\right )\,\left (a^4+2\,a^2\,b^2+b^4\right )}{16\,a\,{\left (a^4+5\,a^2\,b^2+4\,b^4\right )}^2}\right )}{d\,\left (a^2+b^2\right )}-\frac {b\,\ln \left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}{d\,\left (a^2+b^2\right )} \]
[In]
[Out]